## If r and s are the roots of the equation…

## Solution:

We are given that r and s are both roots of the equation x^2 + bx + c = 0, where b and c are constants. We must determine whether rs < 0. To better understand how r and s play a role in the quadratic x^2 + bx + c = 0, let’s go through an example of a quadratic using some real numbers.

x^2 – 2x – 24 = 0

Remember, to factor the given quadratic expression, we need two numbers that multiply to -24 and sum to -2.

We see that the two numbers that sum to -2 and multiply to -24 are -6 and 4.

(x – 6)(x + 4) = 0

x = 6 or x = -4

Thus, we can say that 6 and -4 are the roots of the quadratic x^2 – 2x – 24 = 0. Furthermore, the product of the roots of the quadratic x^2 – 2x – 24 = 0 is negative.

We can generalize this result to say that, in order for the product of the roots to be less than 0 (i.e., rs < 0), then the value of the constant c must also be negative.

**Statement One Alone: **

b < 0

Because b, the coefficient of the x term in the quadratic x^2 + bx + c = 0, can be either negative or positive, we have no information about the value of c.

We can eliminate answer choices A and D.

**Statement Two Alone: **

c < 0

Since c is less than zero we know that the product of r and s is also less than zero. Statement two is therefore sufficient.

**Answer:** B