In the figure above, if the area of the smaller square region is 1/2

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Last Updated on May 10, 2023

GMAT OFFICIAL GUIDE DS

Solution:

We begin by sketching the diagram.

In the figure above, if the area of the smaller square region is 1/2

We are given that the area of triangular region D is 4, and we must determine the length of the side of square A. We must remember that the side of square A is also equal to the length of the hypotenuse of triangle D.

Statement One Alone: 

The area of square region B is 9.

Using the information in statement one, we can determine the side of square B is 3, which is also equal to the height of triangle D. We also know that the area of triangle region D is 4. Thus, we can use the area formula for a triangle to determine the base of triangle D.

area = (base x height)/2

4 = (b x 3)/2

8 = 3b

b = 8/3

Since we know the base and height of right triangle D, we can use the Pythagorean Theorem to determine the length of the hypotenuse. Statement one is sufficient to answer the question. We can eliminate answer choices B, C, and E.

Statement Two Alone: 

The area of square region C is 64/9.

The area of a square is:

Area = s^2

64/9 = s^2

+/-√(64/9) = √s^2

s = 8/3 or -8/3

Since the side of a square can’t be negative, we will use the positive answer of 8/3 to determine that the side of square C is 8/3, which is also equal to the base of triangle D. We also know that the area of the triangular region D is 4. Thus, we can use the area formula for a triangle to determine the height of triangle D.

area = (base x height)/2

4 = (8/3 x h)/2

8 = (8/3)h

24 = 8h

h = 3

Since we know the base and height of right triangle D, we can use the Pythagorean Theorem to determine the length of the hypotenuse. Statement two is sufficient to answer the question.

Answer: D

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