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Last Updated on May 10, 2023
GMAT OFFICIAL GUIDE PS
Solution:
We are given that the product of all integers from 1 to n, inclusive, (i.e., n!) is a multiple of 990.
Thus, n! = 990 x k for some integer k.
Another way to visualize the given information is to say:
n!/990 must be an integer. Thus, n! must contain all the factors of 990.
Notice that 990 = 99 x 10 = 9 x 11 x 10. So in order for n!/990 to be an integer, n must at least be equal to 11, since 11! = 11 x 10 x 9 x … x 3 x 2 x 1.
Answer: B
