# If Q is an odd number and the median of Q…

## Solution:

We are given that Q is an **ODD NUMBER** and that the median of Q **CONSECUTIVE INTEGERS** is 120. Let’s choose a convenient number for Q, such as 3. We can now say:

The median of 3 consecutive integers is 120. Since 120 is the MEDIAN, or middle number of these integers, our 3 integers are the following:

119, 120, 121

The answer choices present us with formulas for the value of the largest integer in the sequence. To determine the correct formula, we therefore will plug 3 in for Q in each answer choice until we get 121.

**A) (Q-1)/2 + 120**

(3-1)/2 + 120 = 1 + 120 = 121.

This **IS** equal to 121.

**B) 3q/2**

(3 x 3)/2 = 9/2 = 4.5

This **IS NOT** equal to 121.

**C) 150q**

150 x 3 = 450

This **IS NOT** equal to 121.

**D) q/100**

3/100 = .03

This **IS NOT** equal to 121.

**E) 150/q**

150/3 = 50

This **IS NOT** equal to 121.

The only answer that is equal to 121.

**Answer: A**