Last Updated on May 10, 2023
We are given that in a box of 12 pens, 3 are defective and thus 9 are not defective. We must determine the probability when two pens are selected, that neither pen will be defective. Thus:
probability(1st pen not defective) x probability(2nd pen not defective)
9/12 x 8/11 = ¾ x 8/11 = 24/44 = 6/11
Answer: C
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