# In a box of 12 pens, a total of 3…

# Solution:

We are given that in a box of 12 pens, 3 are defective and thus 9 are not defective. We must determine the probability when two pens are selected, that neither pen will be defective. Thus:

probability(1st pen not defective) x probability(2nd pen not defective)

9/12 x 8/11 = ¾ x 8/11 = 24/44 = 6/11

**Answer: C**