GMAT OFFICIAL GUIDE PS

Solution:

We are given that a glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. Since we are dealing with a solution, we know that the grams of glucose is proportional to the number of cubic centimeters of solution. Thus, to determine how many grams of glucose would be in the container when we have 45 cubic centimeters of solution, we can set up a proportion.

We can say: “15 grams of glucose is to 100 cubic centimeters of solution as x grams of glucose is to 45 cubic centimeters of solution.” Let’s now set up the proportion and solve for x.

15/100 = x/45

When we cross multiply we obtain:

(15)(45) = 100x

675 = 100x

6.75 = x

There are 6.75 grams of glucose in the solution in the container.

Answer: E

About The Author

Scott Woodbury-Stewart is the founder & CEO of Target Test Prep. A passionate teacher who is deeply invested in the success of his students, Scott began his career teaching physics, chemistry, math, and biology. Since then, he has spent more than a decade helping students gain entry into the world’s top business schools, logging 10,000+ hours of GMAT, EA, GRE and SAT instruction. Scott also served as lead content developer and curriculum architect for the revolutionary courses Target Test Prep GMAT, Target Test Prep EA, Target Test Prep GRE and Target Test Prep SAT Quant.