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On Monday, a person mailed 8 packages…

Jeff Miller June 26, 2015
GMAT OFFICIAL GUIDE PS Solution: To solve this question we can use the weighted average equation. Weighted Average = (Sum of Weighted Terms) / (Total Number of Items) We’ll …
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At a supermarket, John spent 1/2 of his money on fresh fruit

Scott Woodbury-Stewart June 26, 2015
GMAT OFFICIAL GUIDE PS Solution: Let’s let T = total number of dollars spent at the supermarket. With this variable we can set up an equation and determine T. …
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If |y – ½| < 11/2, which of the following…

Jeff Miller June 26, 2015
GMAT OFFICIAL GUIDE PS Solution: We must solve the inequality for two cases: Case 1: (y-1/2) is Positive: |y – ½| < 11/2 y – ½ < 11/2 Add …
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A rectangular garden is to be twice as long as it is wide…

Scott Woodbury-Stewart June 26, 2015
GMAT OFFICIAL GUIDE PS Solution: We first draw a diagram of our garden. The length of the rectangular garden is twice as long is it is wide. Thus, we …
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Which of the following equations is NOT equivalent to…

Scott Woodbury-Stewart May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: To solve this question, we start by FOILing the right hand side of the given equation. 10y^2 = (x+2)(x-2) 10y^2 = x^2 – 4 …
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If n is a positive integer, then n(n+1)(n+2) is…

Scott Woodbury-Stewart May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: The problem is easiest to solve by substituting numbers for n. We’ll try an odd number first and then an even number. For an …
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If 5 – 6/x = x, then x has how many possible values…

Jeff Miller May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: We need to simplify the equation 5 – 6/x = x. We start by multiplying the entire equation by x and we obtain: 5x …
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If a, b, and c are consecutive positive integers and a < b < c…

Scott Woodbury-Stewart May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: The easiest way to solve the problem is to plug in some real numbers for a, b, and c. Since we know they are …
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