List T consists of 30 positive decimals, none of which is an integer…
May 9, 2015
GMAT OFFICIAL GUIDE PS Solution: When reading through this question, notice that we are asked which of the following is a POSSIBLE value of E – S. This tells …
Xavier, Yvonne, and Zelda each try independently to solve a problem…
May 9, 2015
GMAT OFFICIAL GUIDE PS Solution: We are first given the individual probabilities that Xavier, Yvonne, and Zelda WILL solve the problem. We list these below: P(Xavier will solve) = …
If x + 5 > 2 and x – 3 < 7, the value of x must be…
May 9, 2015
GMAT OFFICIAL GUIDE PS Solution: Let’s isolate x in each inequality. x + 5 > 2 x > -3 Next we simplify x – 3 < 7. x – …
If y((3x-5)/2) =y and y#0, then x =…
May 9, 2015
GMAT OFFICIAL GUIDE PS Solution: Answer: A (Note: We can divide both sides by y because it’s given that y does not equal 0. Otherwise, we couldn’t divide both …
If 1 kilometer is approximately 0.6 mile, which of the following…
May 9, 2015
GMAT OFFICIAL GUIDE PS Solution: To solve, we must convert 2 miles to kilometers. We are given that 1 kilometer = 0.6 mile. Thus, we can convert 2 miles …
In the figure above, if PQRS is a parallelogram, then y – x
May 9, 2015
GMAT OFFICIAL GUIDE PS Solution: To solve we need to review some rules about parallelograms. In parallelograms there are two main rules about the relationships between the angles: 1) …
A glucose solution contains 15 grams of glucose per 100 cubic…
May 9, 2015
GMAT OFFICIAL GUIDE PS Solution: We are given that a glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. Since we are dealing with a …
In the equation above, k is a constant. If y = 17 when x = 2
May 9, 2015
GMAT OFFICIAL GUIDE PS Solution: We are given the equation y = kx + 3, where k is a constant. We are also given that y = 17 when …