If a, b, and c are consecutive positive integers and a < b < c…
May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: The easiest way to solve the problem is to plug in some real numbers for a, b, and c. Since we know they are …
Tag: GMAT Solutions
2/(1 + 2/y) = 1…
May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: We need to simplify the equation 2/(1 + 2/y) = 1. We can start by multiplying both sides of the equation by 1 + …
(1/2)⁻³ × (1/4)⁻⁴ × (1/16)⁻¹…
May 21, 2015
GMAT OFFICIAL GUIDE PS – Solution: We start by using the negative exponent rule. When a fractional base is raised to a negative exponent, we can rewrite the expression …
If 1/x – 1/(x+1) = 1/(x+4), then x could be…
May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: We must first eliminate the fractions in the equation 1/x – 1/(x+1) = 1/(x+4). Thus, we will multiply the entire equation by the least …
In the figure above, if z = 50, then x + y =
May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: When looking at the diagram, we want to start with the quadrilateral that contains angles z and y. We must remember that any quadrilateral …
In the rectangular coordinate above, if point R…
May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: We are given that a triangle is created using the x- and y-axes of the coordinate plane. The vertices of the triangle fall at …
Last year, for every 100 million vehicles that traveled…
May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: To solve we will set up a proportion. We know that “100 million vehicles is to 96 accidents as 3 billion vehicles is to …
If 1 + 1/x = 2 – 2/x, then x =…
May 21, 2015
GMAT OFFICIAL GUIDE PS Solution: We need to simplify the equation 1 + 1/x = 2 – 2/x. We start by adding 2/x to both sides of the equation. …